11x^2-1020x+11200=0

Solution for 11x^2-1020x+11200=0 equation:

11x^2-1020x+11200=0

a = 11; b = -1020; c = +11200;
Δ = b2-4ac
Δ = -10202-4·11·11200
Δ = 547600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{547600}=740$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1020)-740}{2*11}=\frac{280}{22}
=12+8/11
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1020)+740}{2*11}=\frac{1760}{22}
=80
$